The area bounded by y = x² + 2, x = 0, x = 2 and the x-axis is:
The area bounded by y = x² + 2, x = 0, x = 2 and the x-axis is:
- A. 20/3 sq units
- B. 16/3 sq units
- C. 8 sq units
- D. 12 sq units
Answer: A) 20/3 sq units
Explanation: Area = ∫₀² (x² + 2) dx = [x³/3 + 2x]₀² = (8/3 + 4) − 0 = 20/3.
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