Evaluate ∫[0 to π/2] (√cot x)/(1 + √cot x) dx.
Evaluate ∫[0 to π/2] (√cot x)/(1 + √cot x) dx.
- A. π/4
- B. π/2
- C. 0
- D. 1
Answer: A) π/4
Explanation: Rewriting as ∫ (√cos x)/(√sin x + √cos x) dx. Using the property ∫ f(x) = ∫ f(a-x), and adding to the original integral, we get 2I = π/2, so I = π/4.
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