If ∫₀¹ (3x² + 2x + k) dx = 0, then k equals:
If ∫₀¹ (3x² + 2x + k) dx = 0, then k equals:
- A. −2
- B. −1
- C. 0
- D. 1
Answer: A) −2
Explanation: ∫₀¹ (3x² + 2x + k) dx = [x³ + x² + kx]₀¹ = 1 + 1 + k = 2 + k = 0 → k = −2.
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