imo class 12 definite integration

A decorative garden patch in Kerala is shaped as the area bounded by y = sin x, x = 0, x = π, and the x-axis. What is the area of this patch in square units?

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A decorative garden patch in Kerala is shaped as the area bounded by y = sin x, x = 0, x = π, and the x-axis. What is the area of this patch in square units?

  • A. 1
  • B. π
  • C. 2
  • D. π/2

Answer: C) 2

Explanation: Area = ∫[0 to π] sin x dx = [-cos x] from 0 to π = -(-1) - (-1) = 1 + 1 = 2 square units.

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