The value of ∫₀^(π/2) log(tan x) dx is:
The value of ∫₀^(π/2) log(tan x) dx is:
- A. π/2
- B. π
- C. 0
- D. −π/2
Answer: C) 0
Explanation: Let I = ∫₀^(π/2) log(tan x) dx. Put x = π/2 − t: I = ∫₀^(π/2) log(cot t) dt = −∫₀^(π/2) log(tan t) dt = −I. So 2I = 0 → I = 0.
0 Answers
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.