Evaluate the definite integral ∫[0 to π/2] sin 2x dx.
Evaluate the definite integral ∫[0 to π/2] sin 2x dx.
- A. 0
- B. 1/2
- C. 1
- D. 2
Answer: C) 1
Explanation: Anti-derivative is -cos(2x)/2. Evaluating from 0 to π/2: (-cos(π)/2) - (-cos(0)/2) = (-(-1)/2) - (-1/2) = 1/2 + 1/2 = 1.
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