During Van Mahotsav, a sapling's growth rate is given by 2/(t+1) cm/day. What is its total growth in the first 9 days? A. 2 ln 10 cm B. ln 9 cm C. 2 ln 9 cm D. ln 10 cm Answer: A) 2 ln 10 cm Explanation: Total growth = ∫[0 to 9] 2/(t+1) dt = [2 ln|t+1|] from 0 to 9 = 2 ln(10) - 2 ln(1) = 2 ln 10 cm.

imo class 12 definite integration

During Van Mahotsav, a sapling's growth rate is given by 2/(t+1) cm/day. What is its total growth in the first 9 days?

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During Van Mahotsav, a sapling's growth rate is given by 2/(t+1) cm/day. What is its total growth in the first 9 days?

Answer: A) 2 ln 10 cm

Explanation: Total growth = ∫[0 to 9] 2/(t+1) dt = [2 ln|t+1|] from 0 to 9 = 2 ln(10) - 2 ln(1) = 2 ln 10 cm.