An Indian Railways train starts from rest. Its acceleration is given by a(t) = 6t m/s². What is the distance covered by the train in the first 2 seconds?
An Indian Railways train starts from rest. Its acceleration is given by a(t) = 6t m/s². What is the distance covered by the train in the first 2 seconds?
- A. 12 m
- B. 4 m
- C. 16 m
- D. 8 m
Answer: D) 8 m
Explanation: Velocity v(t) = ∫ a(t) dt = 3t² (since v(0)=0). Distance s = ∫[0 to 2] v(t) dt = ∫[0 to 2] 3t² dt = [t³] from 0 to 2 = 8 m.
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