Evaluate ∫₀^(π/2) sin 2x dx.
Evaluate ∫₀^(π/2) sin 2x dx.
- A. 0
- B. 1
- C. 2
- D. 1/2
Answer: B) 1
Explanation: ∫ sin 2x dx = −(1/2) cos 2x. From 0 to π/2: −(1/2)[cos π − cos 0] = −(1/2)(−1 − 1) = 1.
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