If ∫₀¹ (x² + kx + 1) dx = 1, then k equals:
If ∫₀¹ (x² + kx + 1) dx = 1, then k equals:
- A. −2/3
- B. −1/3
- C. 0
- D. 1/3
Answer: A) −2/3
Explanation: ∫₀¹ (x² + kx + 1) dx = [x³/3 + kx²/2 + x]₀¹ = 1/3 + k/2 + 1 = 4/3 + k/2 = 1 → k/2 = −1/3 → k = −2/3.
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