Find the area of a triangle with vertices (a, b+c), (b, c+a), and (c, a+b).
Find the area of a triangle with vertices (a, b+c), (b, c+a), and (c, a+b).
- A. a+b+c
- B. abc
- C. 0
- D. 1
Answer: C) 0
Explanation: Applying C2 → C2 + C1 gives (a+b+c) in all elements of column 2. Taking it common leaves C2 identical to C3 (all 1s), so area is 0.
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