If A⁻¹ = [2 −1; −3 2], then matrix A is:
If A⁻¹ = [2 −1; −3 2], then matrix A is:
- A. [2 1; 3 2]
- B. [2 3; 1 2]
- C. [−2 1; 3 −2]
- D. [2 −1; −3 2]
Answer: A) [2 1; 3 2]
Explanation: A = (A⁻¹)⁻¹. det(A⁻¹) = 4−3=1. adj(A⁻¹) = [2 1; 3 2]. So A = [2 1; 3 2]/1 = [2 1; 3 2].
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