A = [2 1; 1 2]. The value of A² − 4A + 3I is:
A = [2 1; 1 2]. The value of A² − 4A + 3I is:
- A. 0
- B. I
- C. 2I
- D. −I
Answer: A) 0
Explanation: A² = [5 4; 4 5]. 4A = [8 4; 4 8]. 3I = [3 0; 0 3]. A²−4A+3I = [5-8+3, 4-4+0; 4-4+0, 5-8+3] = [0 0; 0 0].
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