If |x−1 2; 3 x+1| = 0, then the values of x are:
If |x−1 2; 3 x+1| = 0, then the values of x are:
- A. ±√5
- B. ±√7
- C. ±√11
- D. ±2
Answer: B) ±√7
Explanation: (x−1)(x+1) − 6 = 0 → x² − 1 − 6 = 0 → x² = 7 → x = ±√7.
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