If area of triangle is 4 sq units with vertices (k, 0), (4, 0), (0, 2), then k is:
If area of triangle is 4 sq units with vertices (k, 0), (4, 0), (0, 2), then k is:
- A. 0 or 8
- B. 0 or -8
- C. 8 only
- D. 0 only
Answer: A) 0 or 8
Explanation: Area = ½ |k(0−2) − 0 + 1(8−0)| = 4. |−2k + 8| = 8. So −2k + 8 = 8 (k=0) or −2k + 8 = −8 (k=8).
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