If A is an invertible matrix of order 2, then det(A⁻¹) is equal to:
If A is an invertible matrix of order 2, then det(A⁻¹) is equal to:
- A. det(A)
- B. 1/det(A)
- C. 0
- D. 1
Answer: B) 1/det(A)
Explanation: Since AA⁻¹ = I, taking determinants gives |A||A⁻¹| = 1. Therefore, |A⁻¹| = 1/|A|.
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