A triangle has vertices (a, b+c), (b, c+a) and (c, a+b). Its area is: A. 0 B. a+b+c C. 1/2 D. abc Answer: A) 0 Explanation: Area = (1/2) |a(c+a−a−b) + b(a+b−b−c) + c(b+c−c−a)| = (1/2) |a(c−b) + b(a−c) + c(b−a)| = (1/2)|ac−ab+ab−bc+bc−ac| = 0.

imo class 12 determinants

A triangle has vertices (a, b+c), (b, c+a) and (c, a+b). Its area is:

VAVidaara Admin Asked 6d ago 0 views 0 answers

A triangle has vertices (a, b+c), (b, c+a) and (c, a+b). Its area is:

Answer: A) 0

Explanation: Area = (1/2) |a(c+a−a−b) + b(a+b−b−c) + c(b+c−c−a)| = (1/2) |a(c−b) + b(a−c) + c(b−a)| = (1/2)|ac−ab+ab−bc+bc−ac| = 0.

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