If the system 2x + 3y = 8 and (k+1)x + (2k−1)y = 4k+1 has no solution, then k is:
If the system 2x + 3y = 8 and (k+1)x + (2k−1)y = 4k+1 has no solution, then k is:
- A. 3
- B. 4
- C. 5
- D. 7
Answer: C) 5
Explanation: No solution ⇒ 2/(k+1) = 3/(2k−1) ≠ 8/(4k+1). From 2(2k−1) = 3(k+1), k = 5. At k = 5 the second equation is 6x + 9y = 21, i.e. 2x + 3y = 7, parallel to 2x + 3y = 8 — no solution.
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