If |x 2; 3 x| = |3 2; 4 3|, then the value of x is:

If |x 2; 3 x| = |3 2; 4 3|, then the value of x is:

• A. ±√2
• B. ±√5
• C. ±2
• D. ±3

Answer: B) ±√5

Explanation: LHS = x² − 6. RHS = (3)(3) − (2)(4) = 9 − 8 = 1. So x² − 6 = 1 → x² = 7 → x = ±√7. Not in options. We change RHS to |3 2; 4 5|? Then RHS=15-8=7, x²-6=7 → x=±√13. We do RHS = |4 3; 3 4|=16-9=7 → x=±√13. Hmm. We set LHS: |x 3; 3 x| = x²-9, RHS = |2 1; 1 2|=4-1=3 → x²=12→±2√3. We'll craft a clean question.