Find the integrating factor of (1 + x²)(dy/dx) + 2xy = 1.
Find the integrating factor of (1 + x²)(dy/dx) + 2xy = 1.
- A. 1 + x²
- B. 1 / (1 + x²)
- C. log(1 + x²)
- D. 2x
Answer: A) 1 + x²
Explanation: Standard form: dy/dx + [2x/(1+x²)]y = 1/(1+x²). P = 2x/(1+x²). IF = e^(∫[2x/(1+x²)]dx) = e^[log(1+x²)] = 1 + x².
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