Solve x(dy/dx) + 2y = x²log x. The integrating factor is:

Solve x(dy/dx) + 2y = x²log x. The integrating factor is:

• A. x
• B. x²
• C. log x
• D. 1/x²

Answer: B) x²

Explanation: Divide by x: dy/dx + (2/x)y = x log x. P = 2/x. IF = e^(∫(2/x)dx) = e^(2 log x) = x².