The degree of the differential equation [1 + (dy/dx)²]^(3/2) = c(d²y/dx²) is:
The degree of the differential equation [1 + (dy/dx)²]^(3/2) = c(d²y/dx²) is:
- A. 1
- B. 2
- C. 3
- D. 3/2
Answer: B) 2
Explanation: To make the powers of derivatives integers, square both sides: [1 + (dy/dx)²]³ = c²(d²y/dx²)². The highest order derivative is d²y/dx² and its power is 2. So the degree is 2.
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