Ravi bought a bike for ₹80,000. Its value depreciates at a rate proportional to its current value. Which differential equation represents this situation (V = value, t = time)?
Ravi bought a bike for ₹80,000. Its value depreciates at a rate proportional to its current value. Which differential equation represents this situation (V = value, t = time)?
- A. dV/dt = kV
- B. dV/dt = −kV
- C. dV/dt = k/V
- D. dV/dt = k − V
Answer: B) dV/dt = −kV
Explanation: Depreciation implies a decrease over time, so the rate of change is negative and proportional to the value V. Hence, dV/dt = −kV (where k > 0).
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