∫dx/√(16 − x²) equals:
∫dx/√(16 − x²) equals:
- A. sin⁻¹(x/4) + C
- B. cos⁻¹(x/4) + C
- C. (1/4)sin⁻¹(x/4) + C
- D. tan⁻¹(x/4) + C
Answer: A) sin⁻¹(x/4) + C
Explanation: Standard integral ∫dx/√(a² − x²) = sin⁻¹(x/a) + C. Here a = 4.
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