∫csc x dx is:
∫csc x dx is:
- A. ln|csc x − cot x| + C
- B. ln|csc x + cot x| + C
- C. −cot x + C
- D. ln|tan(x/2)| + C
Answer: A) ln|csc x − cot x| + C
Explanation: Multiply numerator and denominator by (csc x − cot x). Substitute u = csc x − cot x. Result is ln|csc x − cot x| + C.
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