Find ∫ sin⁻¹ x dx
Find ∫ sin⁻¹ x dx
- A. x sin⁻¹ x + √(1-x²) + C
- B. x sin⁻¹ x - √(1-x²) + C
- C. sin⁻¹ x + √(1-x²) + C
- D. x / √(1-x²) + C
Answer: A) x sin⁻¹ x + √(1-x²) + C
Explanation: By parts: u = sin⁻¹ x, dv = 1 dx. uv - ∫ v du = x sin⁻¹ x - ∫ x / √(1-x²) dx. Let 1-x² = t, solving gives x sin⁻¹ x + √(1-x²) + C.
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