∫(x eˣ)/(x+1)² dx is of which type?
∫(x eˣ)/(x+1)² dx is of which type?
- A. Substitution
- B. Integration by parts
- C. Partial fractions
- D. Special form eˣ[f(x)+f'(x)]
Answer: D) Special form eˣ[f(x)+f'(x)]
Explanation: Rewriting x/(x+1)² = 1/(x+1) − 1/(x+1)². Then ∫eˣ[1/(x+1) − 1/(x+1)²] dx = eˣ/(x+1) + C, using ∫eˣ[f(x) + f'(x)]dx = eˣ f(x) + C.
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