∫(csc x cot x) dx is:
∫(csc x cot x) dx is:
- A. −csc x + C
- B. csc x + C
- C. −cot x + C
- D. cot x + C
Answer: A) −csc x + C
Explanation: Since d/dx(csc x) = −csc x cot x, the anti-derivative of csc x cot x is −csc x + C.
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