Evaluate: ∫ x² eˣ dx
Evaluate: ∫ x² eˣ dx
- A. eˣ(x² - 2x + 2) + C
- B. eˣ(x² + 2x + 2) + C
- C. eˣ(x² - 2x) + C
- D. eˣ x² / 2 + C
Answer: A) eˣ(x² - 2x + 2) + C
Explanation: Applying integration by parts twice yields x² eˣ - 2x eˣ + 2eˣ + C = eˣ(x² - 2x + 2) + C.
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