∫(x + 1/x) dx is equal to:
∫(x + 1/x) dx is equal to:
- A. x²/2 + ln|x| + C
- B. x²/2 − 1/x² + C
- C. 1 − 1/x² + C
- D. x²/2 + 1/x² + C
Answer: A) x²/2 + ln|x| + C
Explanation: ∫x dx = x²/2 and ∫(1/x) dx = ln|x|. So the integral is x²/2 + ln|x| + C.
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