Find ∫ x / ((x+1)(x+2)) dx
Find ∫ x / ((x+1)(x+2)) dx
- A. log|x+2|² / |x+1| + C
- B. log|x+1| - 2 log|x+2| + C
- C. 2 log|x+2| - log|x+1| + C
- D. -log|x+1| + log|x+2| + C
Answer: C) 2 log|x+2| - log|x+1| + C
Explanation: x/((x+1)(x+2)) = A/(x+1) + B/(x+2). A = -1/(2-1) = -1. B = -2/(-2+1) = 2. Integral is -log|x+1| + 2 log|x+2|.
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