∫e^(sin x) cos x dx equals:
∫e^(sin x) cos x dx equals:
- A. e^(sin x) + C
- B. e^(cos x) + C
- C. sin x·e^(sin x) + C
- D. cos x·e^(sin x) + C
Answer: A) e^(sin x) + C
Explanation: Let u = sin x, du = cos x dx. ∫eᵘ du = eᵘ + C = e^(sin x) + C.
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