∫cot x dx equals:
∫cot x dx equals:
- A. ln|sin x| + C
- B. ln|cos x| + C
- C. −ln|sin x| + C
- D. ln|sec x| + C
Answer: A) ln|sin x| + C
Explanation: cot x = cos x/sin x. Substitute u = sin x, du = cos x dx. ∫du/u = ln|u| + C = ln|sin x| + C.
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