Using substitution, ∫(2x + 3)⁵ dx equals:
Using substitution, ∫(2x + 3)⁵ dx equals:
- A. (2x+3)⁶/12 + C
- B. (2x+3)⁶/6 + C
- C. 5(2x+3)⁴ + C
- D. (2x+3)⁵/5 + C
Answer: A) (2x+3)⁶/12 + C
Explanation: Let u = 2x+3, then du = 2dx. ∫u⁵ (du/2) = (1/2)(u⁶/6) = u⁶/12 = (2x+3)⁶/12 + C.
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