If ∫f(x)dx = g(x) + C, then ∫f(ax + b)dx is:
If ∫f(x)dx = g(x) + C, then ∫f(ax + b)dx is:
- A. (1/a)g(ax+b) + C
- B. a g(ax+b) + C
- C. g(ax+b) + C
- D. g(x)/a + C
Answer: A) (1/a)g(ax+b) + C
Explanation: Using substitution u = ax+b, du = a dx. ∫f(ax+b)dx = (1/a)∫f(u)du = (1/a)g(u) + C = (1/a)g(ax+b) + C.
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