∫tan²x dx equals:
∫tan²x dx equals:
- A. tan x − x + C
- B. sec²x + C
- C. x − tan x + C
- D. −ln|cos x| + C
Answer: A) tan x − x + C
Explanation: tan²x = sec²x − 1. ∫tan²x dx = ∫sec²x dx − ∫1 dx = tan x − x + C.
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