∫dx/√(x² + 9) is equal to:
∫dx/√(x² + 9) is equal to:
- A. ln|x + √(x²+9)| + C
- B. sinh⁻¹(x/3) + C
- C. Both 0 and 1
- D. tan⁻¹(x/3) + C
Answer: C) Both 0 and 1
Explanation: ∫dx/√(x² + a²) = ln|x + √(x² + a²)| + C or sinh⁻¹(x/a) + C. Both forms are equivalent.
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