∫(dx)/(9 − x²) is equal to:
∫(dx)/(9 − x²) is equal to:
- A. (1/6)ln|(3+x)/(3−x)| + C
- B. (1/3)ln|(3+x)/(3−x)| + C
- C. sin⁻¹(x/3) + C
- D. (1/9)ln|(x+3)/(x−3)| + C
Answer: A) (1/6)ln|(3+x)/(3−x)| + C
Explanation: Form ∫dx/(a² − x²) = (1/(2a))ln|(a+x)/(a−x)| + C. a = 3. So (1/6)ln|(3+x)/(3−x)| + C.
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