∫(eˣ − e⁻ˣ)/(eˣ + e⁻ˣ) dx is equal to:
∫(eˣ − e⁻ˣ)/(eˣ + e⁻ˣ) dx is equal to:
- A. ln(eˣ + e⁻ˣ) + C
- B. ln(eˣ − e⁻ˣ) + C
- C. tan⁻¹(eˣ) + C
- D. ln|eˣ + 1| + C
Answer: A) ln(eˣ + e⁻ˣ) + C
Explanation: Numerator is derivative of denominator. Let u = eˣ + e⁻ˣ, du = (eˣ − e⁻ˣ)dx. ∫du/u = ln|u| + C = ln(eˣ + e⁻ˣ) + C.
0 Answers
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.