Evaluate: ∫ log x dx
Evaluate: ∫ log x dx
- A. x log x - x + C
- B. 1/x + C
- C. log x - x + C
- D. x log x + x + C
Answer: A) x log x - x + C
Explanation: Integrate by parts: u = log x, dv = 1 dx. du = 1/x dx, v = x. uv - ∫ v du = x log x - ∫ x(1/x) dx = x log x - x + C.
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