Evaluate: ∫ eˣ / (e^(2x) + 1) dx
Evaluate: ∫ eˣ / (e^(2x) + 1) dx
- A. tan⁻¹(eˣ) + C
- B. log(e^(2x) + 1) + C
- C. eˣ / (e^(2x) + 1) + C
- D. -tan⁻¹(eˣ) + C
Answer: A) tan⁻¹(eˣ) + C
Explanation: Substitute eˣ = t, eˣ dx = dt. Integral is ∫ dt / (t² + 1) = tan⁻¹(t) + C = tan⁻¹(eˣ) + C.
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