Evaluate: ∫ sec⁴ x tan x dx
Evaluate: ∫ sec⁴ x tan x dx
- A. sec⁴ x / 4 + C
- B. tan⁴ x / 4 + C
- C. sec⁵ x / 5 + C
- D. sec³ x / 3 + C
Answer: A) sec⁴ x / 4 + C
Explanation: Let sec x = t, sec x tan x dx = dt. Integral is ∫ t³ dt = t⁴/4 + C = sec⁴ x / 4 + C.
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