∫(2x + 3)/√(x² + 3x + 2) dx is equal to:
∫(2x + 3)/√(x² + 3x + 2) dx is equal to:
- A. 2√(x²+3x+2) + C
- B. √(x²+3x+2) + C
- C. ln|√(x²+3x+2)| + C
- D. 4√(x²+3x+2) + C
Answer: A) 2√(x²+3x+2) + C
Explanation: Let u = x²+3x+2, du = (2x+3)dx. Integral = ∫du/√u = 2√u + C = 2√(x²+3x+2) + C.
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