If tan⁻¹x + tan⁻¹y + tan⁻¹z = π, then x + y + z equals:
If tan⁻¹x + tan⁻¹y + tan⁻¹z = π, then x + y + z equals:
- A. xyz
- B. 0
- C. 1/xyz
- D. 2xyz
Answer: A) xyz
Explanation: Given tan⁻¹x + tan⁻¹y + tan⁻¹z = π, we know x+y+z = xyz. This is a standard identity.
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