The minimum value of (sin⁻¹(x))² + (cos⁻¹(x))² is:
The minimum value of (sin⁻¹(x))² + (cos⁻¹(x))² is:
- A. π²/8
- B. π²/4
- C. 0
- D. π²/2
Answer: A) π²/8
Explanation: From the quadratic 2a² − πa + π²/4, the minimum occurs at the vertex a = -(-π)/4 = π/4. The value is 2(π/4)² − π(π/4) + π²/4 = π²/8.
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