The value of sin⁻¹(sin(2π/3)) is:
The value of sin⁻¹(sin(2π/3)) is:
- A. 2π/3
- B. π/3
- C. −π/3
- D. 4π/3
Answer: B) π/3
Explanation: 2π/3 is outside [−π/2, π/2]. We write sin(2π/3) = sin(π − π/3) = sin(π/3). So, sin⁻¹(sin(π/3)) = π/3.
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