The value of tan⁻¹(1) + tan⁻¹(2) + tan⁻¹(3) is:
The value of tan⁻¹(1) + tan⁻¹(2) + tan⁻¹(3) is:
- A. π
- B. π/2
- C. 0
- D. π/4
Answer: A) π
Explanation: tan⁻¹1 = π/4. tan⁻¹2 + tan⁻¹3 = π + tan⁻¹((2+3)/(1−6)) = π + tan⁻¹(−1) = π − π/4 = 3π/4. Sum = π/4 + 3π/4 = π.
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