The domain of f(x) = √(sin⁻¹(x)) is:
The domain of f(x) = √(sin⁻¹(x)) is:
- A. [-1, 1]
- B. [0, 1]
- C. [-1, 0]
- D. (0, 1]
Answer: B) [0, 1]
Explanation: sin⁻¹(x) must be non-negative for the square root to be a real number. sin⁻¹(x) ≥ 0 means x is in [0, 1].
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