The domain of f(x) = sec⁻¹(x/2) is:
The domain of f(x) = sec⁻¹(x/2) is:
- A. (-∞, -2] ∪ [2, ∞)
- B. [-2, 2]
- C. (-∞, -1/2] ∪ [1/2, ∞)
- D. (-2, 2)
Answer: A) (-∞, -2] ∪ [2, ∞)
Explanation: For sec⁻¹(y), |y| ≥ 1. So |x/2| ≥ 1, which means |x| ≥ 2. Hence the domain is (-∞, -2] ∪ [2, ∞).
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