imo class 12 inverse trigonometric functions

Find the value of cos[π/3 − sin⁻¹(−1/2)]:

VAVidaara Admin Asked 6d ago 0 views 0 answers

Find the value of cos[π/3 − sin⁻¹(−1/2)]:

  • A. 0
  • B. 1/2
  • C. 1
  • D. √3/2

Answer: C) 1

Explanation: sin⁻¹(−1/2) = −π/6. π/3 − (−π/6) = π/3+π/6 = π/2. cos(π/2) = 0. Option 0 is 0. Correct.

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